The function f is given by f(x)=(3^x+1)/(3^x-3^(-x) ) , for x>0
Show that f(x) > 1 for all x > 0
Solve the equation f(x) = 4
i)Show that f(x) > 1 for all x > 0
Let us assume
When x=0, the value of p=1
Therefore we can conclude that when x > 0, p>1 always.
Since p>1 when x >0
we can conclude from the expression that f(x) >1
ii)Solve the equation f(x) = 4
Given f(x) = 4
Since p is always >0 , we need to take the solution as p=4/3
P= 3^x we assumed initially
Therefore 3^x = 4/3
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