The function f is given by f(x)=(3^x+1)/(3^x-3^(-x) ) , for x>0

Show that f(x) > 1 for all x > 0

Solve the equation f(x) = 4

**Solution:**

**i)Show that f(x) > 1 for all x > 0**

Let us assume

=>

When x=0, the value of p=1

Therefore we can conclude that when x > 0, p>1 always.

=>

Since p>1 when x >0

we can conclude from the expression that f(x) >1

**ii)Solve the equation f(x) = 4**

Given f(x) = 4

=>

Since p is always >0 , we need to take the solution as p=4/3

P= 3^x we assumed initially

Therefore 3^x = 4/3

x =

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