The sum of two integers is 704 and the larger number is 11 more than 8 times the smaller number.Find the two integers.

The sum of two integers is 704 and the larger number is 11 more than 8 times the smaller number. Find the two integers.

Let us say that the two integers are X and Y.

Let X be greater than Y.

Given that the sum of the two integers is 704.

Therefore the first equation would be

We are also given that the larger number is 11 more than 8 times the smaller number.

Hence the equation corresponding to this sentence would be

X+Y=704—> Equation 1

X=8Y +11—>Equation 2

From Equation 1, Y=704-X

Substituting the value of Y =704-x in the equation 2.

X= 8( 704-X)+11

X=5632-8X+11

9X=5643

Therefore the value of y = 704-X=704-627

We can cross-check the answers we got.

Let us plug the values of X and Y in the first equations to check whether they hold good.

X+Y =704

627+77=704

704=704

Therefore the X and Y values we found work good for the equation1.

Let us plug the values of X and Y in the second equations

X=8Y +11

627=8*77+11

627=616+11

627=627

Therefore the X and Y values we found work good for equation 2.

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